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The Expert TA 1 Human-like GX C Secure https://usf16in.theexpertta.com/common/TakeTutorialAssignment.aspx Home Student: amcbeth@iusb.edu My Account Log Out Class I Help Homework 4 Begin Date: 9/19/2018 12:01:00 AM --Due Date: 9/26/2018 11:59:00 PM End Date: 9/26/2018 11:59:00 PM (10%) Problem 6: 9.81 m/s For objects near the surface of the Earth, the universal law of gravitation can be simplified to F= mg, where g = Assignment Status Click here for detailed view Problem Status Completed 50% Part (a) If the mass of the Earth were doubled while at the same time its radius remained constant, by what factor would this change its 2 Completedacceleration due to gravity at it's surface? 3 Completed 4Completed 5 Partial Grade Summary 04( 14( 1/2C2 0% 100% Attempts remaining: 4 per attempt) detailed view Submit Hint I give up! 10 Hints: 0% deduction per hint. Hints remaining: Feedback: 0% deduction per feedback. 50% Part (b) If the radius of the Earth were doubled while at the same time its mass remained constant, by what factor would this change its acceleration due to gravity at the surface? All coment © 2018 Expert TA, LLCExplanation / Answer
g = gravitational acceleration = 9.81 m/sec^2
In terms of mass and radius of earth, g is given by:
g = GMe/Re^2
G = Graviatational Constant = 6.67*10^-11
Part A.
when Re is Constant, then g is directly proportional to Me
So If mass of earth is change then
g2/g1 = Me2/Me1
given that
Me2 = 2*Me1
So,
g2/g1 = 2*Me1/Me1
g2/g1 = 2
g2 = 2*g1
So gravitational acceleration would be doubled. (2 times)
Correct option is D.
Part B.
when Me is constant, we can see that g is inversely proportional to square of radius of earth, So
g2/g1 = (Re1/Re2)^2
Given that
Re2 = 2*Re1
g2/g1 = (Re1/(2*Re1))^2
g2/g1 = (1/2)^2
g2/g1 = 1/4
g2 = (1/4)*g1
So new gravitational acceleration will be one-fourth go initial. (1/4 times)
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