please explain your steps clearly . O-3 points SerPSET9 4 P060 A basketball play

Question

please explain your steps clearly

. O-3 points SerPSET9 4 P060 A basketball player is standing on the floor 10.0 h- 2.18 m. m from the basket as in the figure below. The height of the basket is H-3.05 m, and he shoots the balf at an angle, 8 40.49, with the horizontal from a height of My 10.0 (a) What is the acceleration of the basketball at the highest point in its trajectory? magnitude direction m/s (b) At what speed must the plaver throw the basketball so that the ball goas through the hoco w Need Help? Submit Answer:Save ProgressPrecdice Anothe Version 6.4 points SerPSET9 4 P081

Explanation / Answer

A)

At highest point, ball is subjected to gravity only.

So, acceleration, a = g = 9.8 m/s^2

Direction = downwards

B)

Velocity components along horizontal and vertical directions

Vx = v cos40.4 = 0.762v

Vy = v sin40.4 = 0.648v

Time, t =10/0.762v = 13.12/v

Using relation, y - yo = vy*t + 0.5gt^2

3.05 - 2.18 = 0.648v*(13.12/v) - (0.5 x 9.8) (13.12/v)^2

0.87 = 8.5 - 843.46/v^2

843.46/v^2 = 7.63

V = 10.51 m/s

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