A student travels cross-country from her home to her family’s house which is in
ID: 1881289 • Letter: A
Question
A student travels cross-country from her home to her family’s house which
is in another state. First, she drives from her home to the airport going at a speed of
approximately 60 mph for half an hour. Then she immediately boards the plane which
takes 4.0 hours to travel 2,500 miles across the country. When she arrives at the airport,
she sits and waits for half an hour to get picked up by her family. Lastly, she travels for
half an hour at a speed of 40 mph from the airport to her family’s house. Determine the
average speed of her entire trip from her home to her arrival at her family’s house.
Explanation / Answer
Case 1:
V1=60 mph ,t=0.5 hour
Distance between from her home to airport is
d1=Vt =60*0.5 =30 miles
Case 2:
d2=2500 mile and t=4 hours
Case 3:
d3=0 and t=0.5 hours
Case 4:
V=40 mph and t=0.5 hours
d4 =40*0.5 =20 miles
Average speed of her entire trip from her home to her arrival at her family’s house is
Vavg =total distance /total time
Vavg =(30+2500+0+20)/(0.5+4+0.5+0.5)
Vavg=463.64 mph
if answer was needed in m/s
1 mph =0.44704 m/s
Vavg =463.64*0.44704 =207.26 m/s
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