Question 1 10 In experiment 1, we use the setup seen here. If hlow-1.00 m, hhigh

Question

Question 1 10 In experiment 1, we use the setup seen here. If hlow-1.00 m, hhigh-1.05 m and LTable " 2.00 m, what is the angle e? Give your answer in units of degrees. 10 pts D | Question 2 In experiment 1, we are asked to use our measurement of acceleration to find the velocity of the marble at the end of the table to. Let's assume that we measured an acceleration of 0.98 m/s If we start the marble 180 cm from the end of the table, what is the velocity to? Please give your answer in units of m/s

Explanation / Answer

Ans:-

Question 1

Given data:-hlow = 1m , hhigh = 1.05m, Ltable = 2m

In right angle triangle

Sin = opposite side/Hypotenuse

Opposite side = hhigh –hlow = 1.05m -1m = 0.05m

Sin = 0.05 /2m = 0.025m

= sin-1(0.025)

= 1.43deg

Question2

Here a = 0.98m/s^2, s= 180cm = 180*10^-2m, vin =0

Use kinematics equation

V^2 = Vin^2 + 2as

V^2 = 0 + 2*0.98*180*10^-2

V^2 = 3.528

V = 1.88m/s

V0 = 1.88m/s

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