1. A 265-kV power transmission line carrying 584 A is hung from grounded metal t
ID: 1881141 • Letter: 1
Question
1. A 265-kV power transmission line carrying 584 A is hung from grounded metal towers by ceramic insulators, each having a 1.08×109 resistance. Calculate the power dissipated by 73 of these insulators. (Please note that the ceramic insulators are like resistors that are connected in parallel.)
3. A 568 resistor, an uncharged 1.75 F capacitor, and a 5.9 V emf are connected in series. What is the voltage after one time constant?
R2 Ra 3 2 2 Use the circuit above and Kirchhoff's Rules to determine the current through the R3 resistor. Assume the following details: E1 [E] V, E2 [FI V, r r. r2- al. R1 - [RI, R2- [Q). R3- [S]. Be sure to give a positive valueExplanation / Answer
1)
In parallel connection, the net resistance,
(1/Req) = [ (1/R1) + (1/R2) + ....... + (1/Rn) ] x 73
(1/Req) = 73/R
Req = R/73 = (1.08 x 10^9)/73 = 1.48 x 10^7 Ohm
Power, P = V^2/Req = (265000)^2/ 1.48 x 10^7 = 4746.69 W
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