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Electric Fields of Concentric Cvlinders Data Table 1 VA-VMidvoint1 Data set no.D

ID: 1880730 • Letter: E

Question

Electric Fields of Concentric Cvlinders Data Table 1 VA-VMidvoint1 Data set no.Distance from theVoltage Edge of the center at (r) in Volts For (r) in meters meters(r mid) in meters 0.01m 0.02m 0.03m 0.04m 0.047m 0.05m 0.056m 0.058m 0.06m 0.07m 1.3V 5.2V 6.9V 4 8V 8.8V 9.3V 9.9V 9.3V 10V 10 Terms defined ro-r) rmidpoint- nal ,-8.85 * 10-12 The defining equation for analyzing your data kearranged to: E'--+(-1 (2 r) This formula is in a linear format y-mx+b and allows you to do a linear fit of the x and y components in fitkit to get a slope value. Thus allowing you to form an equation to solve for A (Which is the linear charge density) Place the equation vou are using to solve for The linear charge density in the box below. All points on the paper are 1cm apart from each other and the voltag supply was set at 10vdc. It was 10cm from inner ring to outer ring. I a not sure how to figure out E and the Midpoint.

Explanation / Answer

33.33333

Data set No Distance from the edge of the center (r ) in meter rb-ra Voltage at (r ) in Volt Vb-Va E=Vb -Va /rb-ra Midpoint for r in meter 1/rmid in meter 1 0.01 0 1.3 0 0 2 0.02 0.01 5.2 3.9 390 0.005 200 3 0.03 0.02 6.9 5.6 280 0.01 100 4 0.04 0.03 7.89 6.59 219.6667 0.015 66.66667 5 0.047 0.037 8 6.7 181.0811 0.0185 54.05405 6 0.05 0.04 8.8 7.5 187.5 0.02 50 7 0.56 0.046 9.3 8 173.913 0.023 43.47826 8 0.58 0.048 9.9 8.6 179.1667 0.024 41.66667 9 0.06 0.05 9.3 8 160 0.025 40 10 0.07 0.06 10 8.7 145 0.03

33.33333

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