A rectangular piece of aluminum is 5.60 ± 0.01 cm long and 1.90 ± 0.01 cm wide.
ID: 1880654 • Letter: A
Question
A rectangular piece of aluminum is 5.60 ± 0.01 cm long and 1.90 ± 0.01 cm wide. a) Find the area of the rectangle and the uncertainty in the area. b) Verify that the fractional uncertainty in the area is equal to the sum o the fractional uncertainties in the length and in the width A rectangular piece of aluminum is 5.60 ± 0.01 cm long and 1.90 ± 0.01 cm wide. a) Find the area of the rectangle and the uncertainty in the area. b) Verify that the fractional uncertainty in the area is equal to the sum o the fractional uncertainties in the length and in the widthExplanation / Answer
given rectangular piece of aluminium
l = 5.6+-0.01 cm
w = 1.9 +- 0.01 cm
a. A = lw = 10.64 cm^2
dA/A = dl/l + dw/w = 0.01/5.6 + 0.01/1.9
dA = 0.075 cm^2
A = 10.64 +- 0.075 cm^2
b. dA/A = 0.0070488721
dl/l = 0.00178571428
dw/w = 0.0052631578
hence
dA/A = dl/l + dw/w
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