FULL SCREEN PRINTER VERSION BACK NEXT Chapter 21, Problem 10 of a magnetic field

Question

FULL SCREEN PRINTER VERSION BACK NEXT Chapter 21, Problem 10 of a magnetic field has a magnitude of 0.0481 T and points along the +x axis, while the other component One component has a magnitude of 0.0646 T and points along the -y axis. A particle carrying a charge of +2.81 x 10-5 C +z axis at a speed of 4.13 x 103 m/s. (a) Find the magnitude of the net magnetic force that acts on the particle. (b) Determine the angle that the net force makes with respect to the +x axis. (a) Number Units (b) Number Units

Explanation / Answer

A)

Magnetic force, F = qvB

Field in x axis

F = (2.81 x 10^-5)(4.13 x 10^3)(0.0481) = 0.0056 N

Field in y axis

F = (2.81 x 10^-5)(4.13 x 10^3)(0.0646) = 0.0075 N

Using pytahgorean theorem

Net Force = sqrt(0.0056^2 + 0.0075^2) = 0.0094 N

Part B)

Direction, theta = arctan (0.0075/0.0056)

Theta = 53.25 North of East

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