Simple Circuits - Measurements of Resistance 1. Measure the resistance of each o

Question

Simple Circuits - Measurements of Resistance 1. Measure the resistance of each of the two resistors from your kit and record the values Ri and R. 2. Connect the two resistors in series and measure the total resistance. Record the value Ra. Verify the R-13.8 S2 R2 19.0 formula for resistors connected in series. Explain any difference. Ks-.l 2 3. Connect the two resistors in parallel and measure the total resistance. Record the value Rp. Verify the formula for resistors connected in parallel. Explain any difference. 4.Assume the R from 2. is connected to a battery pack with the terminal voltage 6.00 V. (DO NOT CONNECT THE RESISTORS TO THE BATTERY PACK). Use Ohm's law to compute the current 5. Assume the Rp from 3. is connected to a battery pack with the terminal voltage 6.00 V. (DO NOT CONNECT THE RESISTORS TO THE BATTERY PACK). Use Ohm's law to compute the current. 6. Compare the two values from 4. and 5. Describe your work and your results. Express your results in the appropriate units.

Explanation / Answer

1.

let the resistors are R1 = 13.8 ohm, R2 = 19.0 ohm

2.

if these are connected in series then theoritically the net resistance is

Rs = R1+R2 = 13.8+19.0 ohm = 32.8 ohm

it would be greater than 32.8 ohm when we measure in the circuit because the circuit consisting of the connecting wires and other devices , adding extra resistance in the circuit so the measured value will be greater than the theoritical value.

3. when the resistors are connected in parallel combination in the circuit

the resistance is 1/Rp = 1/R1+1/R2

Rp = R1*R2/(R1+R2)

Rp = (13.8*19.0)/(13.8+19.0) ohm = 7.9939 = 8 ohm

in addition to R1,R2, some resistance in the circuit will be added

4.when connected to a battery of voltage v = 6 V

the current in the circuit is From Ohm's law V = I*R

I = V/R

I = V/Rs = 6/32.8 A = 0.183 A

5.

when connected to a battery of voltage v = 6 V

the current in the circuit is From Ohm's law V = I*R

I = V/R

I = V/Rp = 6/8 A = 0.75 A

.

6

when connected in series the current in the circuit is Is = 0.183 A and in parallel Ip = 0.75 A

and the current across each resistor is same in series combination but the current in parallel combination the current will be different at each resistor according to their resistance

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