Analysis Table 1 V(V) 4.98 E V/m) 0.020 0.040 0.060 3.35 0.100 0.120 0.140 0.160

Question

Analysis Table 1 V(V) 4.98 E V/m) 0.020 0.040 0.060 3.35 0.100 0.120 0.140 0.160 0.180 1. Complete the chart by calculating the average magnitude of the electric field between each two consecutive locations by dividing the difference in the magnitude of the voltages at each of the two locations by the displacement between the two locations. Then find their average value and record it in the last row. (10 points) Calculate the average value of the electric field along the straight line between the two point charges by dividing the difference in the magnitude of the voltages at the two point charges by the displacement between the two point ch 2. arges. Then take the % difference between your two values for the average electric field between the two point charges. (5 points)

Explanation / Answer

Avg E using first and last values

E = (4.98-0) / (0.18-0.02) = 31.125

No difference

V x E 4.98 0.02 na 3.88 0.04 55 3.35 0.06 26.5 2.91 0.08 22 2.55 0.1 18 2.22 0.12 16.5 1.78 0.14 22 1.21 0.16 28.5 0 0.18 60.5 Avg E =31.125

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