2. (20 pts.) The figure below shows a plastic rod with a uniformly negative char

Question

2. (20 pts.) The figure below shows a plastic rod with a uniformly negative charge 0--10C on it. It is bent in a 120° circular are of radius2.0 m and symmetrically placed across an x-axis with the origin at the center of curvature P of the rod a) What is the linear charge density of the rod? b) Determine the electric field vector d due to the rod at the origin. You have to start from the basic definition of the electric field for full credit. determine the object's acceleration vector that an object with a charge of-20 C and a mass of 0.10 kg is placed at P 1.0 3. 60 60

Explanation / Answer

a] linear charge density lambda = Q/[2pi*r *120/360) = -1/[2pi*2/3] = -0.239 C/m

b] Electric field E = 2 k lambda/r * sin 60 degree = 2*9e9*0.239/2* sin 60 degree = 1.86*10^9 N/C i

c] acceleration a = F/m = qE/m = -2*1.86*10^9/0.1 = - 3.72*10^10 m/s^2 i

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