Figure ( a ) shows charged particles 1 and 2 that are fixed in place on an x axi

Question

Figure (a) shows charged particles 1 and 2 that are fixed in place on an x axis. Particle 1 has a charge with a magnitude of |q1| = 15e. Particle 3 of charge q3 = +15e is initially on the x axis near particle 2.Then particle 3 is gradually moved in the positive direction of the xaxis. As a result, the magnitude of the net electrostatic force on particle 2 due to particles 1 and 3 changes. Figure (b) gives the x component of that net force as a function of the position x of particle 3. The scale of the x axis is set by xs = 1.80 m. The plot has an asymptote of F2,net = 1.368 × 10-25 N as x . As a multiple of e and including the sign, what is the charge q2 of particle 2?

Explanation / Answer

Here r = 0.9 where the curve passes through zero in the graph.

Therefore, q1 = +15e

F = 1.368e-25 N

Now,

F = kq1q2 / r2

q2 = Fr2 / kq1

q2 = 5.13e-18 C

we need in terms of e, so dividie by 1.6e-19

q2 = 32e

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.