Verizon An object moving with uniform acceleration has a velocity of 10.0 cmy\'s

Question

Verizon An object moving with uniform acceleration has a velocity of 10.0 cmy's in the positive xdirection when its x coordinate is 3.06 cm. If its x coordinate 2.75 s later is -5.00 cm, what is its acceleration? 13. · -/1 points SerPSE8 2.P029wL The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with acceleration of-5.70 m/s2 for 4.00 s, making straight skid marks 64.6 m long, all the way to the tree. With what speed does the car then strike the tree? mvs Need Help?eTak to Tuter 7 points SerPSE8 2 P036 At t-o, one toy car is set rolling on a straight track with initial position 15.5 cm, initial veloclity 2.5 cm/'s, and constant acceleration 2.30 cm/s2. At the same moment, another toy car is set rolling on an adjacent track with initial position 10.5 cm, initial velocity 5.20 cm/s, and constant zero acceleration. (a) At what time, if any, do the two cars have equal speeds? (Enter NA if the cars never have equal speeds.) (b) What are their speeds at that time? (Enter NA if the cars never have equal speeds.) cm/s (c) At what time(s), if any, do the cars pass each other? (If there is only one time, enter NA in the second blank. If there are two times, enter the smaller time first. If they never pass, enter NA in both blanks) (d) What are their locations at that time? (If there is only one position, enter NA in the second blank. If there are two positions, enter the smaller position first. If they never pass, enter NA in both blanks.) (e) Explain the difference between question (a) and question (c) as clearly as possible.

Explanation / Answer

12)

vi = 10.0 cm/s

d = -5.00 cm - 3.06 cm

= -8.06 cm

t = 2.75 s

use:

d = vi*t + 0.5*a*t^2

-8.06 = 10.0*2.75 + 0.5*a*(2.75)^2

-8.06 = 27.5 + 3.78*a

3.78*a = -35.56

a = -9.41 m/s^2

Answer: -9.41 m/s^2

13)

1st calculate initial velocity:

d = 64.6 m

t = 4.00 s

a = -5.70 m/s^2

use:

d = vi*t + 0.5*a*t^2

64.6 = vi*4.00 + 0.5*(-5.70)*(4.00)^2

64.6 = vi*4.00 - 45.6

vi*4.00 = 110.2

vi = 27.55 m/s

Now to find final velocity use:

vf^2 = vi^2 + 2*a*d

vf^2 = 27.55^2 + 2*(-5.70)*64.4

vf^2 = 759.00 - 734.16

vf^2 = 24.84

vf = 4.98 m/s

Answer: 4.98 m/s

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