In the movie Road Trip, some students are seeking to jump a car across a gap in

Question

In the movie Road Trip, some students are seeking to jump a car across a gap in a bridge. One student, who professes to know what he is talking about ("Of course l'm sure-with physics, l'm always sure."), says that they can easily make the jump. He gives the following data: The car weighs 2100 pounds, with passengers and luggage. Right before the gap, there's a ramp that will launch the car at an angle of 30%. The gap is 10 feet wide He then suggests that they should drive the car at a speed of 50 mph in order to make the jump

Explanation / Answer

part a:

initial x velocity=50*cos(30)=43.3 mph

initial y velocity=50*sin(30)=25 mph

part b:

50 mph=73.333 ft/s

horizontal range=initial velocity ^2*sin(2*angle)/(g)

=(73.3333)^2*sin(2*30)/32

=145.54 ft

part c:

maximum height achieved=v^2*sin^2(theta)/(2*g)

=21 ft

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