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limit of xX O Secure l http, www ebasgn.net/web/Student/Assignment-Responses/subm eBook 10 points Tipler6 2.P065 A car starting at x 48 m accelerates from rest at a constant rate of 6.0 m/s2 (a) How fast is it going after 10 s? m/s (b) How far has it gone (from x 0) after 10 s? (c) What is its average velocity for the interval o Sts 10 s? m/s eBook Submit Answer Save Progress Pradice Another Version ,10 points TiplerS 2P086 A motorcycle officer hidden at an intersection observes a car driven by an oblivious driver who ig 1.77 s after the car has passed the stop sign. She accelerates at 4.9 m/s2 until her speed is 101 intesection (a) How long did it take for the officer to catch up to the car? (b) How fast was the car traveling? mi/h eBook

Explanation / Answer

Given that

initial speed, U = 0 m/sec

a = 6.0 m/sec^2

After t = 10 sec, speed will be

V = U + a*t

V = 0 + 6*10

V = 60 m/sec

Part B.

distance traveled by car in 10 sec will be

d = U*t + 0.5*a*t^2

d = 0*10 + 0.5*6*10^2

d = 300 m

Now distance from origin will be sum of distance traveled (d) and initial distance from origin (x)

D = d + x = 300 + 48

D = 348 m

Part C.

Average Velocity = Distance traveled/Time taken

time taken = 10 sec

distance traveled = 300 m, (from Part B)

So,

V_avg = 300/10

V_avg = 30 m/sec

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