On number one, I don’t know how to find e and I think I messed something up on f
ID: 1878718 • Letter: O
Question
On number one, I don’t know how to find e and I think I messed something up on f/g 1. An arrow is fired from the top of a building with an initial speed of 53.0 m/s at an angle of 40.0 to the horizontal. It strikes a ledge as shown. 65.00 m 23.50 m a) Redraw the picture above and indicate your choice for a coordinate system clearly on your sketch. The x and y axes should be clearly drown and labeled b) Identify the values of the initial conditions based upon your coordinate system? c) Write down the equations of motion that describe this object. In your final answer, replace all known initial conditions and constant values with their appropriate numerical values. d) To what maximum height above the ground does the arrow fly? e) How far (horizontally) from the building does the arrow strike the ledge? f) With what speed does it strike the ledge? 9) What angle does it make in the ledge when it hits A ball is thrown downward from the top of the building shown with an initial speed of 19.00 m/s at an angle of 50.0° to the horizontal. 2. 40.00 m o) Redraw the picture above and indicate your choice for a coordinate system clearly on your sketch. The x and y axes should be clearly drawn and labeled. b) Identify the values of the initial conditions based upon your coordinate system c) Write down the equations of motion that e this object. In your final answer, replace all known initial conditions and constant values with their appropriate numerical values d) How long does it take the ball to hit the g e) With what speed does the ball hit the f) What engle does the ball hit the ground with (this is the same angle an ground? arrow would make if it stuck in the ground--show the angle on a sketchExplanation / Answer
1] Total time to reach the ground (ledge) is:
T = 2(53sin40o/9.8) + t = 6.953 + t
H = uyt + (1/2)gt2
65 - 23.5 = (53sin40)t + 4.9t2
solving this quadratic equation gives, t = 1.057s
therefore, T = 8.01s
in this time, the total horizontal distance traveled is:
D = 53cos40 x 8.01 = 325.21 m
this distance is how far the arrow strikes the ledge from the building.
here, vx = 53cos40 m/s and vy = - [2g(100.71)]1/2 = - 44.43 m/s.
use these values to determine the speed and the direction.
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