1. An object is initially traveling in the +x direction at 39 m/s. A constant ac

Question

1. An object is initially traveling in the +x direction at 39 m/s. A constant acceleration of 8.3 m/s2 is applied in the -x direction. How long does it take the object to stop in seconds?

2. An object is initially traveling in the +x direction at 12 m/s. A constant acceleration of 8.4 m/s2 is applied in the -x direction. What is the displacement it travels, in meters, before it stops?  If in the negative x direction, indicate so with a negative sign.

Please show your work so I understand! thank you!

Explanation / Answer

1) Using equation of kinematics

v = u + at

where v is final velocity and u is initial velocity , a is acceleration

Here v = 0 m/s as object comes to a stop

0 = 39 m/s - 8.3 m/s2*t

t = 4.7 seconds

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2) v2 - u2 = 2ad

where d is the distance travelled

02 - 122 = 2(-8.4)d

-144 = -16.8*d

cancel the negative sign on both sides

d = 8.6 m

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