The magnitude of the electric field is measured as a function of distance for tw

Question

The magnitude of the electric field is measured as a function of distance for two different charge distances. CASE A Distance (mm) 5 10 20 40 E (N/C) 800 200 50 12.5 CASE B Distance (mm) 5 10 20 40 E (N/C) 100 100 100 100 A is outside a long cylinder of charge, while B is near a large sheet of charge OA is outside a sphere of charge, while B is near a large sheet of charge O Case A is near a large sheet of charge while case B is outside a sphere of charge. O Case A is near a large sheet of charge while case B is outside a long cylinder of charge

Explanation / Answer

We know that electric field E= k×q/r2

;here, k= voltzmaan constant

: in large sheet of charge the charge distribution is non uniform and in this case E is inversely proportional to r2.

: in the spehere, the charge distribution is uniform and the magnitude of electric field is same on every point. And the total charge is enclosed in outside border of sphere.

: in the long cylinder of charge, the magnitude of electric field is same on every point, and directed to the outward to the cylinder. And the total charge is enclosed on middle of cylinder.

- so in case A, the E is decreasing with increasing in distance.

So, A is near a large sheet of chrge.

- And in case B the electric field is same on every distance.

So, B is outside a sphere of charge.

So the right answer is 3rd...

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