I need help with both of these please explain 12 pcints A football quarterback r

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I need help with both of these please explain

12 pcints A football quarterback runs 15.0 m straight down the playing field in 2.90 s, He is then hit and pushed 3.00 m straight backward in 1.73 s. He breaks the tackle and runs straight forward another 25.0 m in 5.20 s (a) Calculate his average velocity (in m/s) for each of the three intervals. (Assume the quarterback's iniltial direction is positive. Indicate the direction with the sign of your answer.) 8. My NotesAsk Your Teacher mýs mis m/s (b) Calculate his average velocity (in m/s) for the entire motión, (Assume the quarterback's initial direction is positive. Indicate the direction with the sign of your answer.) m/s Additional Materñials l Reading 9. 1 polnts My Notes Ask Your Teacher A car moves in a straight line at a speed of 60.0 km/h (a) How far will the car move in 3.00 minutes at this speed? km (b) How long will it take the car to move 0.24 km at this speed? Additional Materials TOSHIBA

Explanation / Answer

a)

for interval 1 :

d1 = displacement = 15 m

t1 = time period = 2.90 s

average velocity is given as

v1 = d1/t1

v1 = 15/2.90 = 5.2 m/s

for interval 2 :

d2 = displacement = - 3 m

t2 = time period = 1.73 s

average velocity is given as

v2 = d2/t2

v2 = - 3/1.73 = - 1.7 m/s

for interval 3 :

d3 = displacement = 25 m

t3 = time period = 5.20 s

average velocity is given as

v3 = d3/t3

v3 = 25/5.20 = 4.8 m/s

b)

for the entire motion

average velocity = total displacement/total time

v = (d1 + d2 + d3)/(t1 + t2 + t3)

v = (15 + (- 3) + 25)/(2.90 + 1.73 + 5.20)

v = 3.8 m/s

9.

a)

speed = 60 km/h

time = 3 min = 3/60 hour

distance travelled is given as

distance = speed x time

distance = 60 (3/60)

distance = 3 km

b)

distance = 0.24 km

speed = 60 km/h

time taken is given as

time = distance/speed

time = 0.24/60

time = 0.004 h

time = 0.004 x 3600 sec = 14.4 sec

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