Suppose that a \"fabulouse \" phenotype is controlled by two genes A and B.allel

Question

Suppose that a "fabulouse " phenotype is controlled by two genes A and B.allele A peoduces enough enzyme 1 to convert plain to smashing.Allelel B produces enough enzyme 2 to convert smashing to fbulouse.Allale b produces no enzyme 2. A and B are both autosomal and asoourt independantly.( please explain )
Plain........ >enzyme 1>........ smashing....... > enzyme 2........> fabulous
a)15 fabulouse :1 smashing
b)9 fabulouse : 1 plain
c)9 fabulouse : 3 smashing : 4 plain
d)12 plain :3 fabulouse : 1 smashing
c)13 fabulose :3 plain

Explanation / Answer

TABLE:
Enzyme 1 ---------- Enzyme -2 ----------------  Indivisual
   no -------------------- no --------------------- Plain (case-1)
    no ------------------ yes ---------------------plain (case-2)
   yes ----------------- no -----------------------smashing (case-3)
   yes --------------------- yes ------------------ fabulous (case-3)


A and B are both autosomal and asoourt independantly.


Fraction Enzyme 1 absent = 1/4
Fraction Enzyme 1 present = 3/4

Fraction Enzyme 2 absent = 1/4
Fraction Enzyme 2 present = 3/4

Now
Plain probabilty = Case-1 + case-2 = (1/4)*(1/4) + (1/4)*(3/4) =4/16
Smashing Probability = case-3 = (3/4)* (1/4) = 3/16
Fabulous probability = case=4 = (3/4)* (3/4) = 9/16

So, answer is (c)9 fabulouse : 3 smashing : 4 plain

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