D-3689292enrollmentiD-330449 n/Course/ViewProblem?unit Courses -Technological In
ID: 1878016 • Letter: D
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D-3689292enrollmentiD-330449 n/Course/ViewProblem?unit Courses -Technological Innoo Il Movies 11 Self Development Welcome Mohamme 6: Homework / mework: HW2 Of Ch17&20 eadline: 100% until Monday, September 10 at 11:59 PM Tipler6 17.P.054 1 2 An automobile tire is filled to a gauge pressure of 151 kPa when its temperature is 20°C. (Gauge pressure is the difference between the actual pressure and atmospheric pressure.) After the car has been driven at high speeds, the tire temperature increases to 53C, 1) (a) Assuming that the volume of the tire does not change, and that air behaves as an ideal gas, find the gauge pressure of the air in the tire 166.5 You currently have 3 subhissions for this question. Only 10 submission are allowed. You can make 7 more submissions for this question. kPa Submit Your submissions: 166.5x Computed value: 166.5 Submitted: Monday, September 10 at 3:00 PM Feedback: 2) (b) Calculate the gauge pressure if the volume of the tire expands by 10% kPa Submit You currently have O submissions for this question. Only 10 submission are allowed You can make 10 more submissions for this question. rch DOLLExplanation / Answer
Given
initial values of the tyre are
Pressure P1 =151 kPa ,T1 = 20 0C = 293.15 k later
final pressure P2 =? , Temperature T2 = 53 0C = 53+273.15 k
the volume is remains same inside the tyre so V1 = V2
from ideal gas equation PV = nRT , it can be written as
P2/P1 = T2/T1
susbtituting the values
P2 /(151*10^3) = (53+273.15)/(293.15)
P1 = 167.998 kPa = 168 kPa
2)
if the volume is increased by 10 % of its initial volume then
v2 = V1+0.1V1 = (1.1) V1
from ideal gas equation
P1*V1/T1 = P2*V2/T2
P2 = P1V1T2/(T1(1.1)V1)
P2 = P1*T2/1.1*T1
SUBSTITUTING THE VALUES
P2 = 151*10^3*(53+273.15)/(1.1*293.15) Pa
P2 = 152.725 kPa
The final pressure P2 =152.725 kPa
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