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Question

a ttps://ust44tn.theexpertta.com/Common/TakeTutorialAssignmentaspx 00:00 HWE021I Begin Date:9 (25%) Problem 2: After many observations, we model the force due to a spring using a linear restoring model for small displacements (small meaning it doesn't damage the spring) With one end of a spring with spring constant 36.8 Nim attached to a 18 7:00:00 AMDue Date: 9/1 00:00 AM End Date: I rigid wall, you pull on the other end with steady force of 1.7N Status e for iew Status 50% Part (a) when pulled this way, the spring goes to length 0.25 m what is the relaxed length of the spring in m? Potential 100% cos0 cotan asinacos0 tan() :( 4 5 6 (0% per attempt) detailed view to 0.25 m instead of being stretched. What is the relaxed length of the second spring in m? search 9/10/2

Explanation / Answer

a)

k = spring constant = 36.8 N/m

F = force applied = 1.7 N

xi = initial relaxed length = ?

xf = final stretched length = 0.25 m

using the equation

F = k (xf - xi )

inserting the values

1.7 = (36.8) (0.25 - xi )

xi = 0.204 m

b)

F = force applied = 1.7 N

xi = initial relaxed length = ?

xf = final compressed length = 0.25 m

using the equation

F = k (xi - xf )

inserting the values

1.7 = (36.8) (xi - 0.25)

xi = 0.296 m

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