Verizon LTE 12:23 PM 24% 10 Electric Fields 3-problems... 007 (part 1 of 4) 10.0

Question

Verizon LTE 12:23 PM 24% 10 Electric Fields 3-problems... 007 (part 1 of 4) 10.0 points A uniformly charged ring of radius 5 cm has a total charge of 112 pC. Find the magnitude of the electric field on the axis of the ring at 1.54 cm from the cen- ter of the ring. The value of the Coulomb constant is 8.98755 × 109 N-m2/C2 . Answer in units of N/C. 008 (part 2 of 4) 10.0 points Find the magnitude of the electric field on the axis of the ring at 6.8 cm from the center of the ring Answer in units of N/C. 009 (part 3 of 4) 10.0 points Find the magnitude of the electric field on the axis of the ring at 30 cm from the center of the ring Answer in units of N/C 010 (part 4 of 4) 10.0 points Find the magnitude of the electric field on the axis of the ring at 87.7081 cm from the center of the ring Answer in units of N/C. 011 10.0 points

Explanation / Answer

magnitude of the electric field on the axis of the ring is given by:

E = kQx/(r^2 + x^2)^(3/2)

Part 1.

x = 1.54 cm = 0.0154 m

r = 5 cm = 0.05 m

Q = 112 uC = 112*10^-6 C

So,

E = 8.98755*10^9*112*10^-6*0.0154/(0.05^2 + 0.0154^2)^(3/2)

E = 1.08*10^8 N/C

Part 2.

x = 6.8 cm = 0.068 m

So,

E = 8.98755*10^9*112*10^-6*0.068/(0.05^2 + 0.068^2)^(3/2)

E = 1.14*10^8 N/C

Part 3.

x = 30 cm = 0.3 m

So,

E = 8.98755*10^9*112*10^-6*0.3/(0.05^2 + 0.3^2)^(3/2)

E = 1.07*10^7 N/C

Part 4.

x = 87.7081 cm = 0.877081 m

So,

E = 8.98755*10^9*112*10^-6*0.877081/(0.05^2 + 0.877081^2)^(3/2)

E = 1.30*10^6 N/C

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