a) How far horizontally from the base of the building does the ball strike the g
ID: 1877404 • Letter: A
Question
a) How far horizontally from the base of the building does the ball strike the ground?
b) Find the height from which the ball was thrown.
c) How long does it take the ball to reach a point 10.0 m below the level of launching?
A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 9.40 m/s at an angle of 24.0° below the horizontal. It strikes the ground 5.00 s later (a) How far horizontally frem the base of the building does the ball strike the ground? (b) Find the height from which the ball was thrown. (c) How long does it take the ball to reach a point 10.0 m below the level of launching?Explanation / Answer
A) horizontal distance = V cos theta *t
= 9.4 *cos 24 degree *5
= 42.9 m
B) height = V sin theta *t + 0.5gt^2
= 9.4 sin 24 degree *5 +4.9*5^2
= 141.6 m
C) Using second equation of motion
H = V sin theta *t - 0.5gt^2
10 = 9.4 sin 24 degree *t - 4.9t^2
t =1.09 s answer
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