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llum.ecollege.com/course.html?c .Search ourseid=14891395&OpenV PHY2053 U01 1188 Ines urse Home CH 02 HW ± Rocket Height 15 of 18 Constants Part A A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8 m/s .The 8.00 s until the fuel is exhausted. After that, the rocket is in free fall Find the maximum height ymax reached by the rocket ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 m/s? Write your answer numerically in units of meters. period lasts for time View Available Hint(s) Next > Provide Feedback

Explanation / Answer

given

The intial speed of rocket from the question u =0m/s

accleration period = t = 8.0s

accleration = a = 58.8 m/s2

from the kinematic equation

s = ut + 1/2 * at^2

s = 1/2 * 58.8 m/s2 * (8.0s)^2

s = 1881.6 m

at distance velocity of the rocket= v = u+at

v = 58.8 m/s2 * 8s = 470.4 m/s

So it is the intial speed at the distance = 940.8m

so using this speed height reached = u^2/(2g) = ( 470.4m/s)^2 / (2 * 9.8m/s2)

= 11289,6 m

Now the maxiumu height reached = Hmax =11289,6 m + 1881.6m = 13171.2 m

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