When a charge is placed on a metal sphere, it ends up in equilibrium at the oute

Question

When a charge is placed on a metal sphere, it ends up in equilibrium at the outer surface. Use this information to determine the electric field (in N/C) of 2.0 µC charge put on a 7.0 cm radius aluminum spherical ball at the following two points in space. (Enter the radial component of the electric field.)

When a charge is placed on a metal sphere, it ends up in equilibrium at the outer surface. Use this information to determine the electric field (in N/C) of-2.0 uC charge put on a 7.0 cm radius aluminum spherical ball at the following two points in space. (Enter the radial component of the electric field.) (a) a point 6 cm from the center of the bal (an inside point) N/C (b) a point 14 cm from the center of the ball (an outside point) N/C

Explanation / Answer

Part A.

Electric field inside a metal sphere will be zero.

Since point 6 cm is inside the sphere, So electric field will be zero.

E = 0 N/C

Part B.

Electric field outside sphere is given by:

E = k*Q/r^2

where r = 14 cm = 0.14 m

So,

E = 9*10^9*2*10^-6/(0.14)^2

E = 0.92*10^6 N/C

Since charge is negative so electric field will be towards the sphere, So radial component will be

E = (-0.92*10^6 N/C)

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