A spider crawling across a table leaps onto a magazine blocking its path. The in

Question

A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is 0.860 m/s at an angle of 34.3° above the table, and it lands on the magazine 0.0720 s after leaving the table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters. A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is 0.860 m/s at an angle of 34.3° above the table, and it lands on the magazine 0.0720 s after leaving the table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters.

Explanation / Answer

vy (vertical component of velocity) = 0.860 * sin 34.3 = 0.4846 m/s

Using equation of kinematics, we have

y = vyt + 1/2gt2

y = 0.4846*0.0720 - 1/2*9.8*0.07202

y = 0.0348935 - 0.0254016

y = 9.4919e-3 m

In millimeters,

y = 9.4919 mm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.