tps//usi3Bok theexpertta.com/Common/Take Tutonialássignment.asp Homework 02 Begi

Question

tps//usi3Bok theexpertta.com/Common/Take Tutonialássignment.asp Homework 02 Begin Date: 8/ 5 00:00 PM .. Due Date: 18 5:00:00 PM End Date: 9 (11 %) Problem 4: A bullet in a gun is accelerated from rest from the fring chamber to the end of the ban el at an average rate of 6.25 × 105 m/s2 for 8.4 × 10-4 s. P What is the gun's muzzle velocity (that is, the bullet's final speed), in meters per second? cos) 71819 Aepts ens per ammg cotanasin) acos tan acotan) sinh) osh tanh cotanho END * Degrees Radians

Explanation / Answer

Using 1st equation of motion

v= u + at

= 6.25*10^5* 8.4*10^-4

= 525 m/s

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Comment in case any doubt.. good luck

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