o etisalat 21:21 100% ezto.mheducation.com E connect Mohamed Bin Spring 2018 A c

Question

o etisalat 21:21 100% ezto.mheducation.com E connect Mohamed Bin Spring 2018 A crate of mass 83 kg is held in the position shown. 110.0 poins Determine the magnitude and point of application of the smallest vertical force applied at the bottom of the crate which creates a moment of equal magnitude and opposite sense about E. (Round the final answer to two decimal places.) The magnitude of the smallest vertical force that creates a moment of equal magnitude and opposite sense about E is -N and the port of application is

Explanation / Answer

a) moment = force * distance in perpendicular direction = mg*(0.85-0.6) = 83*g*0.25 = 203.35 N-m

b)let force be F in direction x degrees

moment due to F = moment atE = 203.35

Distance AE^2 = (1.2-0.85)^2 + 0.5^2 , so AE = 0.61

For F to be minimum distance should be maximum,

so distance should be 0.61

so F*0.61 = 203.35, so F = 333.36 N

for distance to be 0.61, foce should be applied in the direction normal to AE line,

so tan x = 0.35/0.5

so x = 34.99 = 35 degrees with horizontal

c)Let force be F

F*distance = moment at E = 203.35

so F*0.85 = 203.35

so F = 239.23 N at point D

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