Pulled Connecting Rod b) The emf around the loop causes a current to flow. How l

Question

Pulled Connecting Rod

b) The emf around the loop causes a current to flow. How large is that current? (Again, use a positive value for clockwise direction.)

c) From your previous results, what must be the electrical resistance of the loop? (The resistance of the rails is negligible compared to the resistance of the rod, so the resistance of the loop is constant.)

d) The rate at which the external force does mechanical work must be equal to the rate at which energy is dissipated in the circuit. What is that rate of energy dissipation (power dissipated)?

Explanation / Answer

(A) induced emf = rate of change of magnetic flux

e = B L v

e = 0.80 x 0.220 x 3.90

e = 0.6864 Volt

(B) F = IL X B

3.90 = (0.220 I) (0.800)

I = 22.16 A  

(C) R = V / I = 0.031 ohm

(D) P = I V = 15.2 Watt

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