& LON-CAPA Air-track glic/X Chegg Study l Guided X1 e Consider The F(x) = Cos hi
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& LON-CAPA Air-track glic/X Chegg Study l Guided X1 e Consider The F(x) = Cos hints05.pdf x- CSecure https//s3.lite.msu.edu/en 33e4fb0fa904cb44bb5f5af72230ce72a8eb2a098ba7c350f6ee7f6c153a95c43e2de5248439ec93ebbc383e9292c3e07107ddb3a3327.. PHY 231 Spring 2018 Messages Courses Help Logout Kodi Marie Feldpauch(Student section: 002) Main Menu Contents Grades O Timer Notes Evaluate Feedback-Print A 0.450 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.700 N to displace the glider to a Course Contents» » Set 05 (02/27 Tu 11:59 PM) Air-track glider and two springs new equilibrium position, x- 0.270 m Find the effective spring constant of the system 2.59 N/m You are correct. Your receipt no. is 160-5399 The glider is now released from rest at x= 0.270 m. Find the maximum x-acceleration of the glider 1.56 m/s 2 You are correct. Your receipt no. is 160-6175 Find the x-coordinate of the glider at time t= 0.470T, where T is the period of the scilation 350 m Calculate the angular velocity and the period, then the time at which you must find the position. Submit Answer Incorrect. Tries 1/12 Previous Tries Find the kinetic energy of the glider at x-0.00 m 9.45x10-2 j You are correct. Your receipt no. is 160-5257 ies Post Discussion Send Feedback 11:49 AM Type here to search @ ^gk 2/23/2018Explanation / Answer
x(t) = Acos(t + ), with ^2 = k/m
A = amplitude = x_max = 0.270 m
is a constant; to find it, set t = 0:
t = 0, x(t) = 0.270 m
0.270 m = (0.270 m)(cos())
cos() = 1
= 0
T = 2 (m/k)
0.470T = 0.4702 (m/k)
t = 0.470*2 (m/k)
t = 0.470*2 (m/k) * (k/m)
= 0.940
x(0.470T) = (0.270 m)cos(0.940 + 0)
= -0.265218 m
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