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Safari File Edit View History Bookmarks window Help [- U.S. 64% CO Fri Feb 23 8:13:16 AM E 0 webassign.net 2.5 kg block is dropped from rest from... 2.3 Kg Block Is Dropped From Rest F EP-HW11-Long Child Whose t Is 350 NS Child Whose Is 350 N hot 50 AM eBook hot 10 AM 8. 0/o.5 points I Previous Answers Tipler6 7.P056. My Notes Ask Your T A child whose weight is 350 N swings out over a pool of water using a rope attached to the branch of a tree at the edge of the pool. The branch is 13 m above ground level and the surface of the pool is 1.8 m below ground level. The child holds on to the rope at a point 10.2 m from the branch and moves back until the angle between the rope and the vertical is 23. When the rope is in the vertical position, the child lets go and drops into the pool. Find the speed of the child at the surface of the pool. m/s Draw a sketch of the situation. Let the system consist of Earth and the child. While one could apply conservation of mechanical energy between the initial point and the bottom of the swing, and then between the bottom of the swing and when the child hits the water, it is more direct to consider the energy transformations between the initial point and when the child hits the water eBook Submit Answer Save Progress Practice Another Version not 16 AM 9. 0.5/0.5 points | Previous Answers Tipler6 11.P.047 soin. My Notes Ask Your T Knowing that the acceleration of gravity on the moon is 0.166 times that on Earth and that the moon's radius is 0.273 RE, find the escape speed for a projectile leaving the surface of the moon. hot 18 AM 2381.19 m/s eBook 23

Explanation / Answer

GPE lost = KE gain

mgh = (1/2) mv^2 (m cancelled out)

v^2 = 2gh

h being change in height.

now. I assume a point 10.2 m from the branch means 10.2 m below the branch, which indicates the rope is 10.2 m long

so simple geometry. h1 = cos (23) 10.2 = 9.39 m

change in height h = 13 - 9.39 + 1.8 = 1.81 m

hence v = (2gh) = V(2 * 9.81 * 1.81) = 5.96 m/s

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