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2nd Ed x The Expert TA | Human-lix C Oli Secure! https://ust35nc.theexpertta.com/common/TakeTutorialAssignment.aspx H: Apps Bookmarks YouTube Hulu H Netflix G Google ill Imported From Safari P Pandora a | o cae 3 Home Student dgrydon@unce.adu My Account Log Out ractice Problems 3 Ganss's Law Begin Date: 1/82018 11:00-00 AM- Due Date: 5/2/2018 11:00:00 PM End Date: 3/2/2018 11.00:00 PM a3%) Problem 2: A circular loop of nius R=22cm is centered at the origin where there is a constant electric field For this problem, assume E.-72NC andr,-142 NC. 33% Part (a) What is the flux through the loop, in Nm C. when the loop is oriented so that its normal vector is in the x-direction? 0,-08712 Grade Summary herial 96% -per attempt) Degrees Radians Fendbacki S deduction per feedback u#33% Part (b) what is the flux through the loop, in Nm2c. direction h the loc pisoni ted so that its normal vector is in the negative 33% Part (c) what is the flat through the loop, in Nm2/C. when the loop is oriented so hat its normal vector i, in be positive t-direction

Explanation / Answer

a) if normal vector is in the x-direction then

flux is phi_E = (Ex i + Ey j )*A i

A is the area of cross section of loop = pi*r^2 = 3.142*11^2 = 380.182 m^2

then

phi_E = (72 i + 142 j)*(380.182)i = 27373.1 N-m^2/C

b) if normal vector is in negative y-direction

A = -380.182 j

then

E*A = (72 i + 142 j)*(-380.182)j = 53985.85 N-m^2/C

c) when normal vector is along positive z direction

then

E*A = (72 i + 142 j)*(380.182)k = 0 N-m^2/C

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