A cubical block of ice 54.5 cm on a side is placed on a level floor over a speck

Question

A cubical block of ice 54.5 cm on a side is placed on a level floor over a speck of dust. Find the location of the image of the speck as viewed from above. The index of refraction of ice is 1.309 cm O above the bottom surface of the ice o below the top surface of the ice Need Help? 3 polints SaP5t9 36.PD9 An object located 34.0 cm in front of a lens forms an image on a screen 8.40 cm behind the lens. (a) Find the focal length of the lens. (b) Determine the magnification. (c) Is the lens converging or diverging? cm o diverging o converging Need Help? e The projection lens in a certain slide projector is a single thin lens. A slide 23.2 mm high is to be projected so that its image fills a screen 1.76 m high. The slide-to-screen distance is 3.09 m. (a) Determine the focal length of the projection lens. (b) How far from the slide should the lens of the projector be placed to form the image on the screen? Need Help? wwhs A contact lens is made of plastic with an index of refraction of 1.44. The lens has an outer radius of curvature of +2.10 cm and an inner radius of curvature of +2.55 cm. What is the focal length of the lens? Check the sign conventions used in the lens-makers' equation. cm

Explanation / Answer

7. Apparent depth = actual depth / n

= 54.5 / 1.309

= 41.6 cm

below the top surface of the ice.

8. p = 34 cm

and q = 8.40 cm

(A) 1/f = 1/p + 1/q

1/f = 1/34 + 1/8.40

f = 6.47 cm

(B) m = -q / p = - 0.247

(C) f is +ve hence converging lens.

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