Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

xy The Expert TAI Human-x e D PeopleSoft session expr expertta.com/Common/TakeTu

ID: 1874951 • Letter: X

Question

xy The Expert TAI Human-x e D PeopleSoft session expr expertta.com/Common/TakeTutorialAssignment.aspx Home I Student: anjali.gandhi@mavs.uta.edu gement 1 Help 2018 2:00:00 PM Due Date: 2/2 End Date: 2/232018 4:0000 AM Homework 3 Begin Date: 2/13/2018 2.00:00 PM-Due Date: 2/22/2018 11:900 PM End (8%) Problem 9: Consider the circuit in the figure, with the current directions defined as shown There are four resistors in this circuit (R1, R2, R3, and R4) and four batteries with emt4-19.5 V,1.5 V, e3-12V,and 4-21.7 V, each 8 wih sterai restace eby markd n the fgure 0.5 Randomized Variables 1-19.5 V 0.5 025 -217V 15 075 Ctheexpertta.com 33% Part (a) Calculate the current 72 in amps. eted eted eted eted leted leted leted Grade Summary Deductions Potential 98% sino cotan asin acos0 atano. acotaro L-sinh() Submissions Attempts remaaing per attempo Degrees Radians pleted Submit Huns Hints:deducthon per lban Hits remning Feedback:deduction per feedback 33', Pan (b) Calculate the current h in amps 531) Part (c) Calculate the current amps

Explanation / Answer

Applying KVL in left loop,

19.5 - 0.5i1 - 20i1 - 6i3 + 1.5 - 0.25 i3 - 15 i1 = 0

35.5i1 + 6.25i3 = 21 ....... (i)

in right side loop,

- 8i2 +12 - 0.5i2 - 0.75i2 - 21.7 + 0.25i3 - 1.5 + 6 i3 = 0

- 9.25i2 + 6.25 i3 = 11.2 ...... (ii)


Applying KCL,  

i1 - i2 - i3 = 0 ..... (iii)

Solving ,

i1 = 0.420 A .....Ans (c)

i2 = - 0.55 A .....Ans (A)

i3 = 0.973 A ......Ans (b)