(13%) Problem 1: A block with mass m1 = 8.5 kg rests on the surface of a horizon
ID: 1874847 • Letter: #
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(13%) Problem 1: A block with mass m1 = 8.5 kg rests on the surface of a horizontal table which has a coefficient of static friction of us 0.62. This block is connected by a pulley system to another block which hangs vertically. The hanging block has mass m2- - 17% Part a) What is the minimum mass, m12 in n kilograms, that will cause the system to move? - 17% Part (b) A second block with mass of 10 kg is placed on top of the first block. What is the new hanging mass,m2min that will cause the system to move? in kilograms, 17% Part (c) The table is inclined at an angle 9, relative to the horizontal in such a way that the pulley is at the highest point and the 10 kg is removed from mj. Write an equation for the magnitude of the normal force, FN, of the block.Explanation / Answer
here,
m1 = 8.5 kg
us = 0.62
a)
let the minimum mass of m2 be m2
equating the forces
us * m1 * g - m2min * g = 0
0.62 * 8.5 = m2min
m2min = 5.27 kg
b)
mass of seccond block , m3 = 10 kg
equating the forces
us * (m1 + m3) * g - m2min * g = 0
0.62 * (8.5 + 10) = m2min
m2min = 11.5 kg
c)
the magnitude of normal force , Fn = ( m1 * g * cos(theta))
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