4. In the figure, two large parallel plates are separated by a distance d-1mm. T

Question

4. In the figure, two large parallel plates are separated by a distance d-1mm. The plate potentials are Vi-50 V and -80 V. A charged particle (1-2 nC) is released from rest just in front of the left plate and is accelerated toward the right plate. VI a. Is the particle positively charged or negatively charged? i. Positive ii. Negative b. What is the magnitude of the electric field in between the plates due to the two parallel plates? Ignore the electric field due to the moving particle. 30,000 v/m Problem 4, cont. c. What is the kinetic energy of the charged particle when it reaches the right plate

Explanation / Answer

a) direction of electric field is from right to left since potential decreases from right plate to left plate

But here force is to the right so by F=qE

Charge must be negative

B) E=V/d = (80-50)/1×10^-3 = 3×10^4 N/C

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