igure below shows a graph of Vx versus t for the motion of a motorcyclist as he

Question

igure below shows a graph of Vx versus t for the motion of a motorcyclist as he starts from rest and moves along the road in a straight line v, (m/s) 10 4-1-6-81-10 1-12, (s) (a) Find the average acceleration for the time interval t-0 to t = 2.0 s. m/s2 (b) Estimate the time at which the acceleration has its greatest positive value. What is the value of the acceleration at that instant? m/s2 (c) When is the acceleration zero? Acceleration is zero when t s and when te (d) Estimate the maximum negative value of the acceleration. m/s2 At what time does it occur? Read It

Explanation / Answer

a)

a_avg=v2-v1/t2-t1

=2-0/(2-0)

=1 m/sec^2

b)

if t=3sec, acceleration is maximum

and

a_max=(v4-v3)/(t4-t3)

a_max=(6-4)/(4-3)

a_max=2 m/sec^2

c)

from the graph, when t=6sec, acceleration is zero

and t>10 sec

d)

maximum negative acceleartion, a=v10-v8/(t10-t8)

=(4-6)/(10-8)

=-1 m/sec^2

maximum negative acceleartion occur when t=8 sec

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