can someone please help me on problem 3? webassign.net | Sy abus - Deaf Culture

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can someone please help me on problem 3?

webassign.net | Sy abus - Deaf Culture No 2A -Sp2018 Assgtos Inbox 1547@mail.fresnostate.edu - Fresno State Mail (b) To sell her plan to the city council, the architect wants to build a model to standard scale, one-thirteenth actual size. How fast should the water flow in the channel in the model? 0.1617 m/s Need Help?Readt 3. -12 points SerCP113.PO59. The determined Wile E. Coyote is out once more to try to capture the elusive roadrunner. The coyote wears a new pair of power roller skates, which provide a constant horizontal acceleration of 15 m/s2. The coyote starts off at rest 70 m from the edge of a cliff at the instant the roadrunner zips by in the direction of the cliff My NotesAsk Your (a) If the roadrunner moves with constant speed, find the minimum speed the roadrunner must have to reach the cliff before the coyote m/s (b) If the cliff is 100 m above the base of a canyon, find where the coyote lands in the canyon. (Assume that his skates are still in operation when he is in "flight" and that his horizontal component of acceleration remains constant at 15 m/s2) m from the base Need Help?ReadIt Submit Answer Save Progress 4. ÷ 3/3 points | Previous Answers SerCP 11 4.P074. My Notes Ask Your Consider the figure below. (Let W1-150 N and W2 62.0 N.) (a) What is the minimum force of friction required to hold the system of the figure above in equilibrium? 62

Explanation / Answer

3) from the formula

d = d0+v0t+1/2at^2

d0 = 0

v0 = 0

d = 1/2at^2

t = sqrt(2d/a) = sqrt(2*70/15) = 3.06 s

v roadrunner = d/t = 70/3.06 = 22.9 m/s

b) the canyon is 100 m deep

100 = 1/2gt^2

g = 10 m/s^2

t = 4.47 s

t tot = 4.47+3.06 = 7.53 sec

dx = 1/2*15*7.53^2 = 425 m

d = 425-70 = 355 m

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