consider the electrostatic force between two particles of equal M=36.2X10^-26kg

Question

consider the electrostatic force between two particles of equal M=36.2X10^-26kg and carrying different charges Q1=11e and Q2=31e, where e denotes the magnitude of the charge on an electron

Suppose you have a 3.7 uC charge and a 225 N?C electric field points due east

Thank you

(6%) Problem 6: Consider the electrostatic force between two particles of equal mass m = 362 × 10-26 kg and carrying different charges q1-l1e and q231e, where e denotes the magnitude of the charge on an electron. - At what distance, in meters, is the electrostatic force between these two particles equal to the weight of one of them?

Explanation / Answer

(6)

Given that,

m = 36.2*10^(-26) kg

q1 = 11e

q2 = 31e

Let the distance = r where electrostatic force is equal to weight of one particle

As given that,

kq1q2 / r^2 = m*g

9*10^9*11*31*(1.6*10^(-19))^2 / r^2 = 36.2*10^(-26) * 9.8

r^2 = 0.02214

r = 0.148 m

(7)

Given that,

q = 3.7 uC

E = 225 N/C

Magnitude of electrostatic force,

F = qE

F = 3.7*10^(-6)*225

F = 8.32*10^(-4) N

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