https://session.masteringphysics.com/myct/itemView?assignmentProblemiD-923940868

Question

https://session.masteringphysics.com/myct/itemView?assignmentProblemiD-923940868 Electric Potential and Capacitance Problem 18.51 Part A to supply to a 6.00 pP capacitor to create a potential difference of 1.50 V across its plates? How much charge does a batery have Submit Request Answer Part B How much energy is stored in the capacitor in this case? Submit Part C How much charge would the battery have to supply to store 1.20 J of energy in the capacitor? Submit Part D What would be the potential across the capacitor in that case? 0 Type here to search e

Explanation / Answer

(A) Q = C V = (6 uF) (1.50 V)

Q = 9 uC or 9 x 10^-6 C

(B) U = C V^2 / 2

U = (6 x 10^-6) (1.50^2) / 2

U = 6.75 x 10^-6 J

(C) U = Q^2 / 2 C

1.20 = Q^2 / (2 x 6 x 10^-6)

Q = 3.79 x 10^-3 C

(D) Q = CV
  
3.79 x 10^-3 = (6 x 10^-6) V

V = 632.5 Volt

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.