F is perpendicular to the wire and points toward the wire Learning Goal Fis is p
ID: 1874280 • Letter: F
Question
F is perpendicular to the wire and points toward the wire Learning Goal Fis is perpendicular to the wire and points away from the wire To practice Tactics Box 24.2 Determining the magnetic force on a moving charged particle evious Ans When a particle of charge q moves with a velocity o in a magnetic field B, the particle is acted upon by a force F exerted by the magnetic field. To find the direction and magnitude of this force, follow the steps in the following Tactics Box. Keep in mind that the right-hand rule for forces shown in step 2 gives the direction of the force on a positive charge. For a negative charge, the force will be in Correct Part C the opposite direction If the magnetic field of the wire is 4.0x10-4 T and the electron moves at 5.0x106 m/s, what is the magnitude F of the force exerted on the electron? Figure 1 of 3 Express your answer in newtons to two significant figures F- 2000 SubmitPrev X Incorrect; Try Again; no points deducted ious Answers Request Answer Provide Feedback Next >Explanation / Answer
F = q (v x B)
F = q v B sin(theta)
where theta is the angle between v and B.
that is alpha. (But you have not provided value of alpha)
F = (1.6 x 10^-19) (5 x 10^6)(4 x 10^-4) sin(alpha)
F = 3.2 x 10^-16 sin(alpha)
if v and B are perpendicular then alpha = 90 deg
F = 3.2 x 10^-16 N
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