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In the figure to the right, M2 has more mass than M1 and M1 has more mass than M

ID: 1874223 • Letter: I

Question


In the figure to the right, M2 has more mass than M1 and M1 has more mass than M3. The questions refer to the magnitudes of tensions and weights. There is friction between the horizontal plane and M2.  M2 is observed to travel at a constant speed. Assume that the pulleys are frictionless and have negligible mass.

Greater than, less than, or equal to:

T3 is ... T2.

T2 is ... T1.

T1 is ... M1 g.
T4 is ... M3 g.

True or False:

M1 accelerates downwards.

The magnitude of the net force on M2 is 0.

M2 12 T3 T1 T4 MI M3

Explanation / Answer

Ans: Here M2>M1>M3, So, M1 accelerates downward.

T3 is less than T2, T2=T3+f
T1=T2(because tension lies in the same string).
T4 is greater than M3g as M3 accelerates up ward. T4=M3a+M3g=T3
T1 is less than M1g as M1 accelerates downwards. T1=M1g-M1a=T2

The magnitude of net force on M2 is F2= M2a=T2-T3-f=0, So M2 is moving with constant speed.

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