Please show all the steps. Thank you! Alternative Exercise 3.102 Part A Constant

Question

Please show all the steps. Thank you!

Alternative Exercise 3.102 Part A Constants Find the distance between the tanks when the round was first fired. Two tanks are engaged in a training exercise on level ground. The first tank fires a paint-filled training round with a muzzle speed of 253 m/s at an angle 11.2° above the horizontal while advancing toward the second tank with a speed of 16.5 m/s relative to the ground. The second tank is retreating at a speed of 39.0 m/s relative to the ground, but is hit by the shell. You can ignore air resistance and assume the shell hits at the same height above ground from which it was fired. x=2260 m Previous Answers Correct Part B Find the distance between the tanks at the time of impact. ? 2434.505 | Submit Request Answer XIncorrect: Try Again: 5 attempts remaining

Explanation / Answer

speed of the first tank,

u1=253 m/sec

v1=16.5 m/sec

theta=11.2 degrees

speed of the second tank,u2=39 m/sec

B)

velocity component along vertical direction,

uy=u*sin(theta)

uy=253*sin(11.2)

uy=49.14 m/sec

and

time of flight, T=2*uy/g

T=2*49.14/9.8

T=10.03 sec

and

velocity component along horizontal direction,

ux=u*cos(theta)

ux=253*cos(11.2)

ux=248.2 m/sec

at the time of impact,

x=ux*T

x=248.2*10.03

x=2489.44 m

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