1. (40 POINTS) In the following problem, the positive x-direction is rightward a
ID: 1874041 • Letter: 1
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1. (40 POINTS) In the following problem, the positive x-direction is rightward and the velocities written are components along x. The velocity component is positive if the motion is rightward, otherwise it is negative. You are a member of the crew on the ”Starfighter" spaceship. indexed by “s". An enemy spaceship (indexed by "e") is moving toward your Starfighter ship with speed, as measured in your frame. Ives- 0.500c. The enemy ship fires a missile toward you with speed Vme |- 0.800c relative to the enemy ship. Suppose the proper length Lo of the missile is 2.00 m to an observer at rest with respect to missile. Suppose the missile's rest mass is m-200.00 kg (a) (15) What is the magnitude of the missile's momentum relative to yoiu (b) (15) What is the length of the missile relative to you? (c) (10) Suppose a "light-clock at rest on the missile emits a signal every 2.00 seconds. What would be the time interval between signals as measured by you? es mc ene starfighter mis sile 2/3/2017 TEST 1 SP 15 PHYSICS 5 Section 2. (40 POINTS) An electron is accelerated through a potential difference starting from rest. At the end of it's acceleration, the kinetic energy K is 4 times the electron's rest energy mc', i.e., the final kinetic energy K = 4mc. Note: Below upper case V refers to potential and lower case v refers to speed. (a) (30 points) What is the speed v of the electron at the end of it:s acceleration? Express v as a fraction of the speed of light c (b) (10 points) What is the value V of the potential difference (in Volts)? Assume the electron charge has magnitude e 1.6x10 19 C. Note: Electron mass = 9.11x10°r kg.Explanation / Answer
As per chegg guide lines I am working first problem, please post remaining question in the next post
(a)
from the addition of velocities
v= v'+u/ 1+ v'u/c^2
= 0.5c+0.8c/1+ (1+ (0.5c)(0.8c)/c^2) = 0.928 c
momentum P = m v/ sqrt 1- (v/c)^2 = 200(0.928 c)/sqrt 1- (0.928c/c)^2 = 1494.443* 10^8 m/s
(b)
L = Lo sqrt ( 1- ( v/c)^2 = 2.0* sqrt 1- (0.928c/c)^2 = 0.745 m
(c)
t'= t/ sqrt 1-(v/c)^2 = 2/sqrt (1- (0.928/c)^2 = 5.36 s
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