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The labeled graphs below represent the upward trajectories of 4 bodies, two slid

ID: 1874028 • Letter: T

Question

The labeled graphs below represent the upward trajectories of 4 bodies, two sliding upwards on frictionless inclines and two in free flight. Note that all 4 bodies reach the same maximum height (9 meters) after traveling from the same initial elevation (0 m).


• The initial speed of R is  greater than less than equal to  that of P.
• The time of travel of P is  greater than less than equal to  that of R
• The initial speed of P is  greater than less than equal to  that of Q.
• The time of travel of R is  greater than less than equal to  that of N.
• The time of travel of N is  greater than less than equal to  that of Q
• The initial speed of Q is  greater than less than equal to  that of N.

10- 7 3 2 i1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 Relative horizontal position, x, (m)

Explanation / Answer

the initial speed of R is less than of P, slope of curve R is lesser than that of P, slope determines speed.

thus velocity of P is higher so it will reach faster than R.

Slope of P and Q are almost same at the start. so their speed is equal.

time travel for N is greater than time travel in Q. also the initial speed is higher for Q.

N and R will take same time to reach

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