Part A If F B = 710 N , and F C = 540 N , determine the magnitude of the resulta

Question

Part A

If FB = 710 N , and FC = 540 N , determine the magnitude of the resultant force acting on the flag pole. (Figure 1)

Express your answer to three significant figures and include the appropriate units.

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Part B

Determine the coordinate direction angle of the resultant force acting on the flag pole.

Express your answer to three significant figures and include the appropriate units.

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Part C

Determine the coordinate direction angle of the resultant force acting on the flag pole.

Express your answer to three significant figures and include the appropriate units.

SubmitRequest Answer

Part D

Determine the coordinate direction angle of the resultant force acting on the flag pole.

Express your answer to three significant figures and include the appropriate units.

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1 of 1

Part A

If FB = 710 N , and FC = 540 N , determine the magnitude of the resultant force acting on the flag pole. (Figure 1)

Express your answer to three significant figures and include the appropriate units.

FR =

SubmitRequest Answer

Part B

Determine the coordinate direction angle of the resultant force acting on the flag pole.

Express your answer to three significant figures and include the appropriate units.

=

SubmitRequest Answer

Part C

Determine the coordinate direction angle of the resultant force acting on the flag pole.

Express your answer to three significant figures and include the appropriate units.

=

SubmitRequest Answer

Part D

Determine the coordinate direction angle of the resultant force acting on the flag pole.

Express your answer to three significant figures and include the appropriate units.

=

SubmitRequest Answer

Return to AssignmentProvide Feedback

Figure

1 of 1

6 m Fc 3 m 3 2 m

Explanation / Answer

BA = B - A = (2, - 3, 0 ) - (0, 0, 6)

= 2i - 3j - 6k

|BA| = sqrt(2^2 + 3^2 + 6^2) = 7

BAcap = BA / |BA| =0.286 i - 0.429 j - 0.857 k

CA = 3i + 2j - 6k

similarly, CAcap = 0.429 i + 0.286 j - 0.857 k

Fnet = FB + Fc = 710 (BAcap) + 540 (CAcap)

= 434.4 i - 150 j - 1071.4 k

(A) magnitude = sqrt(434.4^2 + 150^2 + 1071.4^2)

= 1166 N  

(B) alpha = cos^-1(434.4 / 1166)

= 68 deg

(C) beta = 97.4 deg

(D) gamma = 23.2 deg  

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