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)1% https//www.webassign.net/webStudent/ Assignment-Responses/last?dep 18257779 c | | Search. "XPhy 231 6-10 HW #5 eChegg Study Guided Solu AACE Organic English to French, Italian, nr: 06 Franca s interactifDashboard w WebAssign Spling Learn ng Login p Anazor com Online m/s ( in the direction ofthe m Need Help? atiee SerPSE9 6P MNotes Ask Whenever two Apollo astronauts were on the surface of the Moon, a third astronaut orbited the Moon. Assume the orbit to be circular and 900 km above the surface of the the acceleration due to gravity is 0.726 m/s. The radius of the Moon is 1.70 x 10s m. a) Determine the astronaut's orbital speed. 1113.88x Your response differs from the correct answer by more than 10%. Double check your calculations. m/s (b) Determine the period of the orbit. 9640.11 Your response differs from the correct answer by more than 10%. Double check your calculations, s Need Help? Read t 5. 33 points I Previous Answers SerPSE9 6.P 008 WI My Notes Ask Your T Consider a con cal pendulum with a bob of mass m = 88.0 kg on a string of length· of the circular path and +j to be upward.) 100 m that makes a i gie s- soo, N th the ier cat consider. ibe tovarts he enter

Explanation / Answer

(a) Here, r = 1.70 x 10^6 + 900 x 10^3 = (1.70 + 0.90) x 10^6 = 2.60 x 10^6 m

And given that, a = 0.726 m/s^2

Now, a = v^2/r

=> v^2 = a*r

=> v = sqrt [a*r] = sqrt [0.726 x 2.60 x 10^6]

=> v = 1.888 x 10^3 m/s

(b) Again we have the expression -

a = (w^2)r

=> a = (4pi^2/T^2) * r

=> T^2 = [(4pi^2)/a]*r

=> T = sqrt[((4 x 3.141^2) / (0.726))x 2.60 x 10^6)] = 11.89 x 10^3 sec = 11890 sec.

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