ingPhysics: CH02 HWw 4 of 18 Part B constant speed on a straight highway. Initia

Question

ingPhysics: CH02 HWw 4 of 18 Part B constant speed on a straight highway. Initially, the car and the of 19.5 m/s, and the After ty 4.00 s, the motorcycle starts to rate of 8.00 m/s . The motorcycle catches up with the car at some time t2 are both traveling at the same speed between them is 60.0 m at a car? In other words, find to-ti Express the time numerically in seconds using three significant figures. Figure 1011 Previous Anwer Incorrect; One attempt remaining; Try Again Part with the car (at time t2)? Should you need to use an answer from a previous part, make sure you use the Answer numerically in meters using three significant figures. MacBook Air

Explanation / Answer

partA

the motor moving with a constant speed for the time t1 .hence up to the time t1 the graph between position and time is a straight line .after that it accelerated up to the time t2. hence ,there will be a exponentential increament in the position time graph . Finally both car and motorcycle are met after time t2 .

Hence , suitable graph for this situation is graph A.

part B

The displacement of the car from t1 is:

Dcar = 60 + 19.5*t

The displacement of the motorcycle from t1 is

Dmc = 19.5*t + 0.5*8*t^2 = 19.5*t + 4*t^2

The motorcycle catches up with the car when Dcar = Dmc

so, 60 + 19.5*t = 19.5*t + 4*t^2

t = t2 - t1 = sqrt(60/4) = 3.87 s

partC

x = vo*(t2 -t1) + 1/2*a*(t2 -t1)2

x = 19.5*3.87 + 0.5*8*(3.87)2

x = 1356.42 m

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