Name. Partners Date HoMEWORK FOR LAB 3 ELECTRICAL AND GRAVITATIONAL POTENTIAL 1.

Question

Name. Partners Date HoMEWORK FOR LAB 3 ELECTRICAL AND GRAVITATIONAL POTENTIAL 1. Ineach of the drawings below, E = 4.0 N/C and d = 1.5 m. For each diagram calculate: a. The work done by the electric field in moving a +50 × 10-9 C charge from A to B b·The difference between the charge's potential energy at B and at A. c. The potential difference between A and B. 2. What is the relationship between equipotential surfaces (or lines in two dimensions) and the direction of electric field lines? 3. How much work is done moving a charge along an equipotential surface (line)? Explain. LECTRICAL AND GRAVITATIONAL POTENTIAL

Explanation / Answer

A)

a)

The charge moves in the direction of electric field , i.e parallel to it.

W = 4 x 1.5 x 5 x 10^-9 J

W = 3 x 10^-8 J

b)

Since the movement is perpendicular to electric filed , the work done is Zero.

c)

Here we will see the displacement in the direction of electric field.

W = 4 x d*cos(30) x 5 x 10^-9

W = 4 x 1.5 x cos30 x 5 x 10^-9

W = 2.595 x 10^-8 J

B).

Difference in charge's potential energy is basically the negative of the work done by electric filed found in part (a).

so

a) -3 x 10^-8 J.

b) 0

c) -2.595 x 10 ^-8 J

C

Potential differnce is the - E*d*cos(angle with E)

a)

-4 x 1.5 x cos(0) V = -6 V

b)

Zero since perpendicular.to electric field cos 90 = 0.

c)

-4 x 1.5 x cos(30) = -4 x 1.2975 V = - 5.19 V

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